purnachand

purnachand

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Statistics3
Answer:

You read a research report of the differences in weight gain in infants on enriched formula (sample 1) and soy-based formula (sample 2). The findings are reported as: t=6.79; p=.006; Confidence interval of the mean difference: 4.76 to 8.43.

What is the hypothesis decision?

 

Reject the null hypothesis

Accept the null hypothesis

Sample 2 is larger than sample 1: the soy-based formula showed greater weight gain in infants than the enriched formula

Sample 1 is larger than sample 2: the enriched formula showed greater weight gain in infants than the soy-based formula

 

You read a research report of the differences in weight gain in infants on enriched formula (sample 1) and soy-based formula (sample 2). The findings are reported as: t=6.79; p=.006; Confidence interval of the mean difference: 4.76 to 8.43.

What is the conclusion statement?


Accept the null hypothesis

Sample 2 is larger than sample 1: the soy-based formula showed greater weight gain in infants than the enriched formula

Reject the null hypothesis

Sample 1 is larger than sample 2: the enriched formula showed greater weight gain in infants than the soy-based formula

 

You read a research report in which the confidence interval of the mean difference is reported as -1.45 to 3.46. You know from this information that:


There is no statistically significant differences between samples

There is a statistically significant difference between samples; the mean of sample 1 is larger than the mean of sample 2

There is a statistically significant difference between samples; the mean of sample 1 is smaller than the mean of sample 2

Answer: Step-by-step explanation: Here the test statistics is t=6.79; and corr...
Answer: Step-by-step explanation: option----A) -2.54 to 1.38 since the p-value...

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