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29 Dec 2020

A fully charged parallel-plate capacitor remains connected to a battery while you slide a dielectric between the plates. What happens to the following quantities (i) C (ii) Q (iii) ΔV

Booster class
Electricity and Magnetism
Skill
Understanding capacitors
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29 Dec 2020
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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

A parallel-plate capacitor of plate separation d is charged to a potential difference . A dielectric slab of thickness d and dielectric constant  is introduced between the plates while the battery remains connected to the plates. (a) Show that the ratio of energy stored after the dielectric is introduced to the energy stored in the empty capacitor is . (b) Give a physical explanation for this increase in stored energy. (c) What happens to the charge on the capacitor?

 

A parallel-plate capacitor of plate separation d is charged to a potential difference . A dielectric slab of thickness d and dielectric constant is introduced between the plates while the battery remains connected to the plates. (a) Show that the ratio of energy stored after the dielectric is introduced to the energy stored in the empty capacitor is . (b) Give a physical explanation for this increase in stored energy. (c) What happens to the charge on the capacitor?

 

A parallel-plate vacuum capacitor is connected to a battery and charged until the stored electric energy is Image for A parallel - plate vacuum capacitor is connected to a batteryand charged until the stored electric energy is U. The battery is removed, and then a dielectric material with dielectric constant Kis inserted into the capacitor, filling the space between the plates. Finally, the capacitor is fully discharged through a resistor (which is connected across the capacitor terminals).
A.)Find Image for A parallel - plate vacuum capacitor is connected to a batteryand charged until the stored electric energy is U_r, the the energy dissipated in the resistor.
Express your answer in terms ofImage for A parallel - plate vacuum capacitor is connected to a batteryand charged until the stored electric energy is Uand other given quantities.
15026_a.jpg
B.) Consider the same situation as in the previous part, except that the charging battery remains connected while the dielectric is inserted.   The battery is then disconnected and the capacitor is discharged. For this situation,what is Image for A parallel - plate vacuum capacitor is connected to a batteryand charged until the stored electric energy is U_r, the energy dissipated in the resistor?
Express your answer in terms ofImage for A parallel - plate vacuum capacitor is connected to a batteryand charged until the stored electric energy is Uand other given quantities.
15026_b.jpg

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