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6 Oct 2020
A parallel-plate capacitor of plate separation d is charged to a potential difference . A dielectric slab of thickness d and dielectric constant is introduced between the plates while the battery remains connected to the plates. (a) Show that the ratio of energy stored after the dielectric is introduced to the energy stored in the empty capacitor is . (b) Give a physical explanation for this increase in stored energy. (c) What happens to the charge on the capacitor?
A parallel-plate capacitor of plate separation d is charged to a potential difference . A dielectric slab of thickness d and dielectric constant is introduced between the plates while the battery remains connected to the plates. (a) Show that the ratio of energy stored after the dielectric is introduced to the energy stored in the empty capacitor is . (b) Give a physical explanation for this increase in stored energy. (c) What happens to the charge on the capacitor?
Aerielle Anne BeltranLv10
3 Dec 2020