The proton synchrotron at Fermilab accelerates protons to a kinetic energy of 950 GeV. At this energy, calculate (a) the speed, expressed as a fraction of the speed of light; and (b) the magnetic field at the proton orbit that has a radius of curvature of 750 m. (The proton has a rest energy of 938 MeV; it is necessary to use relativistic formulas here.)

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Related questions

The synchrotron at the Fermi Laboratory has a diameter of5.0 km.Protons circling in it move atapproximately the speed of light.

(a) How long does it take a proton to completeonerevolution?

1 s

(b) The protons enter the ring at an energy of 8.0 GeV. Theygain2.2 MeV each revolution. How manyrevolutions must they travelbefore they reach 400 GeV ofenergy?

2 revolutions

(c) How long does it take the protons to be accelerated to400GeV?

3 s

(d) How far do the protons travel during this acceleration?

4 km

any help would be great
lifesaver?

The synchrotron at the Fermi Laboratory has a diameter of5.0 km.Protons circling in it move atapproximately the speed of light.

(a) How long does it take a proton to completeonerevolution?
1 s
(b) The protons enter the ring at an energy of 8.0 GeV. Theygain2.2 MeV each revolution. How manyrevolutions must they travelbefore they reach 400 GeV ofenergy?
2 revolutions
(c) How long does it take the protons to be accelerated to400GeV?
3 s
(d) How far do the protons travel during this acceleration?
4 km

any help would be great

Protons having a kinetic energy of 5.00 MeV are moving in the positive x-direction and enter a magnetic field of B= 0.0500 k^ T in the directed out of the plane of the page, and extending from x = 0 to x = 1.00 m as shown in figure P28.50.

(a) Ignoring relativistic effects, find the angle between the initial velocity vector of the proton beam and the velocity vector after the beam emerges from the field.