A quantity of a monatomic ideal gas undergoes a process in whichboth its pressure and volume are doubled as shown in the figureabove. What is the energy absorbed by heat into the gas during thisprocess?
For unlimited access to Homework Help, a Homework+ subscription is required.
Half a mole of an ideal monatomic gas at a pressure of 415 kPa anda temperature of 300 K expands until the pressure has diminished to170 kPa.(a) Find the final temperature and volume, the work done, and theheat absorbed by the gas if the expansion is isothermal.? K? L? kJ (work done)? kJ (heat absorbed)(b) Find the final temperature and volume, the work done, and theheat absorbed by the gas if the expansion is adiabatic.? K? L? J (work done)? J (heat absorbed)
286 mols of an ideal monatomic gas undergo the process shown in the PV plot (Figure 1). The process A→B is adiabatic. In the plot below, Volume A=1.60 m3, Volume B=3.48 m3 and Pressure A=3.14 atm.
What is Pressure B?
How much heat is added as the gas goes from B→C?
What is ΔEint as the gas goes from C→A?
The only form of energy possessed by molecules of a monatomic ideal gas is translational kinetic energy. Using the results from the discussion of kinetic theory in Section 10.5, show that the internal energy of a monatomic ideal gas at pressure P and occupying volume V may be written as U = 32PV
