Textbook ExpertVerified Tutor
25 Nov 2021
Given information
A capacitor of capacitance C= 250pF.
Step-by-step explanation
Step 1.
It is known that the energy of a capacitor of capacitance C is calculated as,
where V is is the potential difference.
In this problem we need to get four times the initial energy.
Therefore, final energy,
Also according to the problem we need to get four times the energy by using an extra capacitor with C.
Thus we must add the new capacitor in parallel with C, as in parallel connection the capacitance is added.
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