Question

You are performing a two-tailed test. If a = .01, find the positive critical value, to three decimal places. License Points possible: 3 This is attempt 1 of 3. Test the claim that the mean GPA of night students is larger than 2.7 at the 0.025 significance level. The null and alternative hypothesis would be: Ho:p> 0.675 H.: p = 0.675 Hou > 2.7 Ho: < 2.7 H:P < 0.675 H :P + 0.675 H:4 < 2.7 H :u > 2.7 H:P < 0.675 H : = 2.7 H:p > 0.675 H:47 2.7 The test is: right-tailed two-tailed left-tailed 0 0 0 Based on a sample of 35 people, the sample mean GPA was 2.73 with a standard deviation of 0.08 The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis Points possible: 3 License This is attempt 2 of 3. Score on last attempt: (0, 0, 0.75, 0.75). Score in gradebook: (0, 0, 0.75, 0.75), Out of: (0.75, 0.75, 0.75, 0.75) You wish to test the following claim (H) at a significance level of a = 0.10 Hou = 76.8 H: #76.8 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n =23 with mean M = 85.9 and a standard deviation of SD = 13.2. What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than or equal to) a greater than a This p-value leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 76.8. There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 76.8. The sample data support the claim that the population mean is not equal to 76.8. There is not sufficient sample evidence to support the claim that the population mean is not equal to 76.8. A political candidate has asked you to conduct a poll to determine what percentage of people support her. If the candidate only wants a 3% margin of error at a 99% confidence level, what size of sample is needed? Give your answer in whole people. License Points possible: 3 This is attempt 1 of 3. Test the claim that the proportion of people who own cats is smaller than 60% at the 0.05 significance level. The null and alternative hypothesis would be: Ho:p> 0.6 H:< 0.6 Hou > 0.6 Ho:P < 0.6 H:P < 0.6 H: > 0.6 H:N < 0.6 H:p > 0.6 O Ho:p = 0.6 Ho:u= 0.6 H:P +0.6 H M # 0.6 The test is: right-tailed two-tailed left-tailed 0 Based on a sample of 100 people, 54% owned cats The p-value is: (to 2 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesis Points possible: 3 License This is attempt 2 of 3. Score on last attempt: (0, 0.75, 0.75, 0). Score in gradebook: (0, 0.75, 0.75, 0), Out of: (0.75, 0.75, 0.75, 0.75)