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A 0.105 g sample of a monoprotic acid of unknown molar mass is dissolved in water and titrated with 0.1003 M NaOH. The equivalence point is reached after adding 28.68 mL of base. What is the molar mass of the unknown acid?
A 0.105 g sample of a monoprotic acid of unknown molar mass is dissolved in water and titrated with 0.1003 M NaOH. The equivalence point is reached after adding 28.68 mL of base. What is the molar mass of the unknown acid?
9 Apr 2023
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Hubert KochLv2
13 Dec 2019
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