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A 30.0 mL analyte is made up of 0.155 g of an unknown monoprotic acid. The equivalence point is reached after 19.7mL of a 0.050 M NaOH solution is titrated into the analyte. Based on this finding, determine the molar mass of the unknown acid.
A 30.0 mL analyte is made up of 0.155 g of an unknown monoprotic acid. The equivalence point is reached after 19.7mL of a 0.050 M NaOH solution is titrated into the analyte. Based on this finding, determine the molar mass of the unknown acid.
Reid WolffLv2
17 Dec 2019
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