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13 Dec 2019

I am having trouble understanding this question. I don't need every single value worked out I just want to understand what to do so I can work the rest out myself!

The question is written exactly as writtten:

The pK of an acid is 4.16. Calculate the pH of a solution of the acid if it is titrated to the following extents. Use the value associated with your student ID: extent of titration with NaOH, percent

0

1

2

3

4

5

6

7

8

9

28

71

33....

The istructions say,

Show all Calculations, give your pH value to two decimal places

My Student ID number is 1

I really just need help understanding the problem and how I should work it out, I don't want every single pH answer to the solution of the acid if it was titrated to all of the extents that are requested. I truly just want to learn and understand!

Thanks for your help and time!

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Nestor RutherfordLv2

17 Dec 2019

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I need help answering this question. PLEASE READ IT CAREFULLY. I just want to double make sure if my answer is wrong or right but the steps to solve the problem is ITS asking to solve for the pH at equivalence

Calculating the exact pH is, as usual in titration problems, a solution stoichiometry (moles/molarity/volume) problem followed by an equilibrium composition problem.

First, you need to calculate the molarity of HC2H5CO2 after the titration reaction has run. This is the stoichiometry problem.

Then you can set up a reaction table and use the K a equation for HC2H5CO2 to calculate the equilibrium molarity of H3O +This is the equilibrium problem

The graph below is a titration curve of three differentsolutions. Solution I is titrated with a base of a lower pH. Rankthe solutions in terms of the strength of the acid in thesolution.

Apparantly, the correct answer is "there is no difference amongthe strength of the acids," however I'm not entirely sure why. Theexplanation states that graph II has a higher concentration of acidthan graph III, but why would this shift the titration curve to theright? Shouldn't the curve just become less compressed at higherconcentrations as shown in the following figure?

Or would this only be the case if the question stated explicitlythat only the identity of the analyte was the same in all 3solutsions? In other words, does this mean solution II must be a ofa different concentration as well as a different identity? Whatsignificance is it that solutions II and III still have the sameequivalence point? Also, I don't understand why a titrant of lowerpH (i.e. in the titration of solution I) would decrease theequivalence point. Wouldn't you then need more titrant toneutralize the analyte if the pH of the titrant were lower? Cansomeone please thoroughly explain? Thank you!

I'm working on a project I need some help with (BTW I asked my teacher and I am allowed to ask for help). If there was anything I wasn't clear on please tell me because I'm just hopelessly lost on this. Also just to note this actually has a fair bit of chemistry in it but because it's all related to electricity and there is no chemistal engineering subject Tab I put it here.

Okay so in this project we have a hypothetical scenario. In this scenario I'm on an abandoned island and I need to power a satellite for 97 minutes at 12 volts at 30 amps and 5 volts at 45 amps. But on this island are various supplies including a 1987 V8 engine which I think will provide 12 volts at 30 amps. Now what I need is fuel to get it going. I have 4 deep friers full of oil, 3 cases of magnum bottles of champagne, salt water from the ocean, 21 2 gallon jars of pickled eggs, and 33-5 gallon containers of italian salad dressing, and 23 #10 cans of tomato sauce. There is also an abandoned moonshine still. So using the oil from the friers, the champagne, and getting the oil out of the salad dressing I should be able to get a decent amount of biofuel correct? I also have 9 full 20# propane tanks and I read that propane can be used to make fuel burn more efficiently by taking the place of the air injection. If there anything else from this list that I could make into fuel of some kind? What about Moonshine everything I read mentions sugar and yeast which I don't think I have either of.

So assuming I have that all worked out okay that gets me my 12 volts at 30 amps. But I still need the 5 volts at 45 amps. And one solution I was thinking of was making voltic cells. Amoung the materials I have to work with that are of use here are some 1/2'' and 3/4'' copper pipes, 8 roles of aluminum foil, 23 20ft lengths of 6 in. sch. 40 PVC pipe, 17 20ft lengths of 4in. sch. 40 PVC pipe, and 9 20ft lengths of 2 in. Sch. 40 PVC pipe. I also have some cans of cold galvanizing spray paint ( meaning I have zinc), and various containers including a lot of PVC pipe, 55 gallon plastic drums, and a complete set of commercial pots and pans. I also have various wires but I'll put that asside for now. I also have access to some PH adjust (down)

Now what I want to do is make a battery set up that can deliver 5 volts at 45 amps for 97 minutes.

I know I can make several battery cells and connect them in series and parallel to get the desires voltage and current. But i'm having trouble figuring out what my voltage and amperage would be for each cell. Also how long would the charge last?

I read something called aluminum-air batteries but I'm not clear on how they are made or if they are ideal for what I need. Would using the pickling solution from the pickled eggs as my electrolyte be better than using the salt water? Or should I separate the vinegar out of the salad dressing and us that? Would using the PH adjust (down) help?

I tried looking up some reduction charts but those were all in aqueous. What I was able to get was that for copper and aluminum it was about 2 v potential and for copper Zinc it was about 1.01 v. Is this correct? For a base line lets say I just use the PVC pips, copper pipe, aluminum foil, Salt water, and for wiring I use copper wire. if I"m correct and I get about 2 V from each battery how do I find my amperage? What part of all this affects the current and how would I calculate it? Would using a different kind of wire be better? I have access to a couple different kinds.

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