Question

The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line,y=mx+b.

Order	Integrated Rate Law	Graph	Slope
0	[A]=−kt+[A]0	[A] vs. t	−k
1	ln[A]=−kt+ln[A]0	ln[A] vs. t	−k
2	1[A]= kt+1[A]0	1[A] vs. t	k

Part A The reactant concentration in a zero-order reaction was 0.100 M after 195 s and 1.50×10−2 M after 330 s . What is the rate constant for this reaction?

Part B What was the initial reactant concentration for the reaction described in Part A?

Part C The reactant concentration in a first-order reaction was 6.90×10−2 M after 10.0 s and 8.10×10−3 M after 100 s . What is the rate constant for this reaction?

Part D The reactant concentration in a second-order reaction was 0.130 M after 215 s and 6.10×10−2 M after 845 s . What is the rate constant for this reaction? Please show your work.