1
answer
0
watching
236
views
6 Nov 2019

The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line,y=mx+b.

Order Integrated Rate Law Graph Slope
0 [A]=−kt+[A]0 [A] vs. t −k
1 ln[A]=−kt+ln[A]0 ln[A] vs. t −k
2 1[A]= kt+1[A]0 1[A] vs. t k

A) The reactant concentration in a zero-order reaction was 5.00×10−2M after 185 s and 4.00×10−2M after 355 s . What is the rate constant for this reaction?

Express your answer with the appropriate units.

B)

What was the initial reactant concentration for the reaction described in Part A?

Express your answer with the appropriate units.

C)

The reactant concentration in a first-order reaction was 8.10×10−2M after 50.0 s and 7.00×10−3M after 95.0 s . What is the rate constant for this reaction?

Express your answer with the appropriate units.

D)

The reactant concentration in a second-order reaction was 0.790 M after 120 s and 7.60×10−2M after 775 s . What is the rate constant for this reaction?

Express your answer with the appropriate units.

For unlimited access to Homework Help, a Homework+ subscription is required.

Tod Thiel
Tod ThielLv2
4 Jun 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
discord banner image
Join us on Discord
Chemistry Study Group
Join now

Related textbook solutions

Related questions

Weekly leaderboard

Start filling in the gaps now
Log in