1
answer
0
watching
325
views
17 Nov 2019

The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line,y=mx+b.

Order Integrated Rate Law Graph Slope
0 [A]=?kt+[A]0 [A] vs. t ?k
1 ln[A]=?kt+ln[A]0 ln[A] vs. t ?k
2 1[A]= kt+1[A]0 1[A] vs. t k

Part A

The reactant concentration in a zero-order reaction was 5.00×10?2M after 175 s and 4.00×10?2M after 400 s . What is the rate constant for this reaction?

Part B

What was the initial reactant concentration for the reaction described in Part A?

Part C

The reactant concentration in a first-order reaction was 6.40×10?2M after 50.0 s and 4.60×10?3M after 60.0 s . What is the rate constant for this reaction?

Part D

The reactant concentration in a second-order reaction was 0.730 M after 210 s and 6.40×10?2M after 705 s . What is the rate constant for this reaction?

For unlimited access to Homework Help, a Homework+ subscription is required.

Jamar Ferry
Jamar FerryLv2
15 Aug 2019

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
discord banner image
Join us on Discord
Chemistry Study Group
Join now

Related textbook solutions

Related questions

Weekly leaderboard

Start filling in the gaps now
Log in