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11 Dec 2019

So,I add 0,5370g ofNa2S2O3*5H2O in 100mlof water. What is the molarity of[S2O32-]?

Then I weight 38,4972g of 43,25mg/g H2O4dilute in 250ml of water. What is the molarity of[H2O4]?

What is the molarity of both solutions?

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Tod Thiel
Tod ThielLv2
13 Dec 2019

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Related questions

Write the equation for calculating the initial rates of each of these reactions. Rate = รŽย”[I2]/รŽย”t The indicator changed color when all the thiosulfate ions, S2O32-, were used up. Upon the instant the solutions were mixed, you calculated a molarity of S2O32- (from Q 9). Since the concentration of thiosulfate changed from this value to zero this is the value of รŽย”[S2O32-].

What is the value of รŽย”[I2] at the point of the color change for each of the runs? (Show your work) Consider the balanced reaction for the clock step:

I2(aq) + 2 S2O32-(aq) รขย†ย’ 2 I-(aq) + S4O62-(aq)

The indicator changed color when all the thiosulfate ions, S2O32-, were used up. Upon the instant the solutions were mixed, you calculated a molarity of S2O32- (from Q 9). Since the concentration of thiosulfate changed from this value to zero this is the value of ?[S2O32-]. What is the value of ?[I2] at the point of the color change for each of the runs? (Show your work) Consider the balanced reaction for the clock step: I2(aq) + 2 S2O32-(aq) ? 2 I-(aq) + S4O62-(aq) ?

(Q9) Upon the instant the solutions are mixed, what is the concentration (in M) of thiosulfate for all of the trials? (Show your work)

[Na2S2O3]1: .012M (5 drops)(.012M)= (48 drops)M2

V1 ( in drops): 5 drops

V2 ( in drops): 48 drops

[Na2S2O3]2: .00125 M


molarity or a dilution

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