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A Mg(OH)2 solution is standardized by titrating withKHP(MW=204.23g/mol). KHP is a monoprotic acid.

a. If 35.36 ml of the basic solution neutralizes 0.844g of KHP,calculate the molarity of the Mg(OH)2.


b. If 44.62 ml of the Mg(OH)2 solution neutralizes 0.545g of anunknown monoprotic acid, calculate the molar mass of the acid.



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Casey Durgan
Casey DurganLv2
28 Sep 2019
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Related questions

 
Calculate the amount of ascorbic acid in the Vitamin C tablet in (mg).  =?

A vitamin C (ascorbic acid) tablet was dissolved in approximately 50 mL of distilled water and titrated with the standardized NaOH solution. From 
the results of this titration, the mg of ascorbic acid in the tablet was calculated.
Molecular formulas:
Potassium hydrogen phthalate: HKC8H4O4
Acetic acid: C2H4O2
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Assume that all 3 acids are monoprotic acids.



Mass of KHP used for standardization (g) 0.5464
Volume of NaOH required to neutralize KHP (mL) 13.31
Volume of vinegar sample titrated (mL) 5.00
Volume of NaOH required to neutralize vinegar in (mL) 8.40
Molecular weight of ascorbic acid (g/mol) 176.1271
Volume of NaOH required to neutralize ascorbic acid in Vitamin C tablet (mL) 13.85

What is the Molecular Weight of KHP (HKC8H4O4) in g/mol? 204.2220 
How many moles of KHP were used in the standardization of the NaOH solution? 0.002595
Calculate the concentration of NaOH solution in (mol/L). 0.188433
Calculate the molarity of the vinegar solution (mol/L). 0.303377

 Calculate the molarity of an HCl solution if 26.4 mL of the solution neutralizes 30.0 mL of a 0.120 molar solution of Ba(OH)2.

I need the answer of #2 < #1 is answered because we need it in#2 >

1.A 0.2816g sample of KHP required 29.68 mL of sodium hydroxide toreach the phenolphthalein end point. Calculate the molarity of NaOHsolution.
#1 answer Given that mass of KHP = 0.2816 g
We know that
The molar mass of KHP = 204.22 g/mol
? Number of moles of KHP = mass / molarmass
= 0.2816 g/204.22 g/mol
= 0.00138 mol
We know that one mole of NaOH neutralizes one mole ofKHP
? The number of moles of NaOH = NUmber of molesof KHP
= 0.00138 mol
The volume of NaOH = 29.68 mL
= 0.02968 L
Hence te molarity of NaOH = moles / volume inliters
= 0.00138 mol / 0.02968 L
= 0.04646M

2. A volume of 20.22 mL of the Naoh solution described in Q.1 wasneeded to titrate 10.06 mL of acetic acid of the phenolphthaleinend point. Find the concentration of the acetic acid solution.

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