Question

I need the answer of #2 < #1 is answered because we need it in#2 >

1.A 0.2816g sample of KHP required 29.68 mL of sodium hydroxide toreach the phenolphthalein end point. Calculate the molarity of NaOHsolution.
#1 answer Given that mass of KHP = 0.2816 g
We know that
The molar mass of KHP = 204.22 g/mol
? Number of moles of KHP = mass / molarmass
= 0.2816 g/204.22 g/mol
= 0.00138 mol
We know that one mole of NaOH neutralizes one mole ofKHP
? The number of moles of NaOH = NUmber of molesof KHP
= 0.00138 mol
The volume of NaOH = 29.68 mL
= 0.02968 L
Hence te molarity of NaOH = moles / volume inliters
= 0.00138 mol / 0.02968 L
= 0.04646M

2. A volume of 20.22 mL of the Naoh solution described in Q.1 wasneeded to titrate 10.06 mL of acetic acid of the phenolphthaleinend point. Find the concentration of the acetic acid solution.