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10 Nov 2019
Physical Chemistry III
An electron in a conjugated hydrocarbon is confined to an effective distance of 8.27 A. Use the uncertainty principle to calculate the minimum uncertainty in the speed of the electron. Some constant, please get any needed other constants h = 6.63x10^-34 J.s h= h/2pi= 1.05x10^-34 J.s c = 3.00x10^8 m/s = 300x10^10 cm/s NA = 6.02x 10^23 mol^-1 k= 1.38 x 10^-23 J/K R = 8.31 J/mol-K R = 8.31 Pa-m3/mol-K me = 9.11x10^-31 kg (electron mass) 1 J = 1 kgm^2/s^2 1 A = 10^-10 m k.NA = R 1 amu 1.66x10^-27kg 1 atm. = 1.013x10^5 Pa 1 eV = 1.60 x 10^-9 J Mass of neutron = 1.675 x 10^-27 kg|
Physical Chemistry III
An electron in a conjugated hydrocarbon is confined to an effective distance of 8.27 A. Use the uncertainty principle to calculate the minimum uncertainty in the speed of the electron. Some constant, please get any needed other constants h = 6.63x10^-34 J.s h= h/2pi= 1.05x10^-34 J.s c = 3.00x10^8 m/s = 300x10^10 cm/s NA = 6.02x 10^23 mol^-1 k= 1.38 x 10^-23 J/K R = 8.31 J/mol-K R = 8.31 Pa-m3/mol-K me = 9.11x10^-31 kg (electron mass) 1 J = 1 kgm^2/s^2 1 A = 10^-10 m k.NA = R 1 amu 1.66x10^-27kg 1 atm. = 1.013x10^5 Pa 1 eV = 1.60 x 10^-9 J Mass of neutron = 1.675 x 10^-27 kg|
Keith LeannonLv2
30 May 2019