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10 Nov 2019
Physical chemistry III
The effective length of the n system in the conjugated linear hydrocarbon hexa-1, 3, 5-triene, C6H8, is 7.4 A. By treating the n electrons as particles in a one-dimensional box, calculate the wavelength of the lowest energy absorption in the electronic spectrum of hexa-1,3,5-triene. En = n^2h^2/8mL^2 Some constant, please get any needed other constants h = 6.63 x 10^-34 J.s h = h/2pi = 1.05 x 10^-34 J-s c = 3.00 x 10^8 m/s = 3.00 x 10^10 cm/s NA = 6.02x 10^23 mol^-1 k = 1.38 x 10^-23 J/K R = 8.31 J/mol-K R = 8.31 Pa-m^3/mol-K me = 9.11 x 10^-31 kg (electron mass) Mass of neutron = 1.675 x 10.27 kg 1 J = 1 kg.m^2/s^2 1 A = 10^-10 m k.NA = R 1 amu = 1.66 x lO^-27 kg 1 atm. = 1.013 x 10^5 Pa 1 eV = 1.60 x 10^-19 J
Physical chemistry III
The effective length of the n system in the conjugated linear hydrocarbon hexa-1, 3, 5-triene, C6H8, is 7.4 A. By treating the n electrons as particles in a one-dimensional box, calculate the wavelength of the lowest energy absorption in the electronic spectrum of hexa-1,3,5-triene. En = n^2h^2/8mL^2 Some constant, please get any needed other constants h = 6.63 x 10^-34 J.s h = h/2pi = 1.05 x 10^-34 J-s c = 3.00 x 10^8 m/s = 3.00 x 10^10 cm/s NA = 6.02x 10^23 mol^-1 k = 1.38 x 10^-23 J/K R = 8.31 J/mol-K R = 8.31 Pa-m^3/mol-K me = 9.11 x 10^-31 kg (electron mass) Mass of neutron = 1.675 x 10.27 kg 1 J = 1 kg.m^2/s^2 1 A = 10^-10 m k.NA = R 1 amu = 1.66 x lO^-27 kg 1 atm. = 1.013 x 10^5 Pa 1 eV = 1.60 x 10^-19 J
Bunny GreenfelderLv2
13 Aug 2019