Verified Documents at University of Ottawa

Browse the full collection of course materials, past exams, study guides and class notes for MAT 1300 - Mathematical Methods I at University of Ottawa verified by our community.
PROFESSORS
All Professors
All semesters
Termeh Kousha
spring
14
Hung-Chang Liao
fall
14

Verified Documents for Hung-Chang Liao

Class Notes

Taken by our most diligent verified note takers in class covering the entire semester.
MAT 1300 Lecture Notes - Lecture 1: Negative Number
A function has an output for every input. Note: an input cannot have two different outputs. This is not a function (input 3 has two different outputs)
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MAT 1300 Lecture Notes - Lecture 2: Asymptote, Coefficient, Graphing Calculator
People model demand and supply by linear functions. Demand= d(p)= -0. 7p+ 8. 7 (slope is negative (-0. 7) as demand reduces when price increases) The e
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MAT 1300 Lecture Notes - Lecture 3: Logarithm, Asymptote
1 xa . xb = xa + xb. 2 (xa)b =( xa . xa . xa . xa ) b times = xab these laws extend to real numbers a,b. Note : x-a . xa = x0 =1. Note: (xy)2 = xy xy=
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MAT 1300 Lecture 4: MAT 1300 LECTURE 4 –LIMITS and continuity
Take a function say f(x) = x2 we like to compute the slope of a tangent line. Tangent line a line which touches the graph pf f at exactly one point. Th
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MAT 1300 Lecture 5: MAT 1300 –LECTURE 5 – RULES
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MAT 1300 Lecture Notes - Lecture 6: Product Rule
Continuation of lecture 5 f(x) = |x| what is f(0. 00001) ? answer =1. Let f be a function the line tangent to the graph of f at (a, f(a)) is the line p
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MAT 1300 Lecture Notes - Lecture 7: Maxima And Minima, Inflection
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MAT 1300 Lecture Notes - Lecture 8: Maxima And Minima
Let f be a function a number c is called a critical number if either: f(c) =0. If c is a critical number then (c, f(c)) is called a critical point. The
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MAT 1300 Lecture Notes - Lecture 9: Maxima And Minima, Minimax
Mat 1300 lecture 9- global maximum and minimum & curve sketching. If f is continuous on [a,b] then f has a global max and a global min somewhere in [a,
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MAT 1300 Lecture 10: MAT 1300 LECTURE 10 -REVIEW
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MAT 1300 Lecture 11: MAT 1300 LECTURE 11- IMPLICIT DIFFERENTIATION
Consider the circle given by the equation x^2 +y^2 = 25. One method is to solve y in terms of x y^2 = 25-x^2 y = +or - (sqrt (25- x^2) (3,4) is on the
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MAT 1300 Lecture Notes - Lecture 12: Integral, Riemann Sum
Mat 1300 lecture 12 - the definite integral. A car travels at a constant speed of 40 km/hr for 2 hours how far has it gone. Answer : 40 km/hr *2 hr = 8
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MAT 1300 Lecture 13: MAT 1300 LECTURE 13 - THE FUNDAMENTAL THEOREM AND ANTIDIFFERENTIATION
Mat 1300 lecture 13 - the fundamental theorem and antidifferentiation. Recall that if f(x) represents the distance travelled then f"(x) represents the
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MAT 1300 Lecture Notes - Lecture 14: Antiderivative
By the fundamental theorem of calculus to evaluate the definite integral b a f(x) dx. We can try to find an antiderivative f of f (meaning f"(x) =f(x)
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