CHE 2A Lecture Notes - Lecture 3: Tin(Iv) Chloride, Roman Numerals, Nitric Acid

22 views4 pages
5 Oct 2018
School
Department
Course
Professor
haihang6688 and 38622 others unlocked
CHE 2A Full Course Notes
19
CHE 2A Full Course Notes
Verified Note
19 documents

Document Summary

Column 1 = alkali metals = +1. Column 2 = alkaline earth metals = +2. ---- skip over transition metals ---- (rarely any pattern in oxidation state) Column 17 = -1 (second column from the left) But in peroxide (o2 2-) , oxygen = -1. But in hydride (h 1-), hydrogen = -1. When hydrogen is in front of others in the formula (i. e. h2o), hydrogen is +1. When hydrogen is written last, (i. e. cah2), hydrogen is -1 each. Charge of molecule = sum(elemental charges/oxidation state) 2 = (1)*(oxidation state of sulfur) + (4) * (-2) Note: hydrogen is proton here, not hydride, since it"s not written last & therefore has +1 charge. Total charge = 0, so carbon = +4. Elements in elemental state have oxidation state 0. Any metal on its own = oxidation state of 0. List of diatomics x2 , oxidation = 0. Monoatomic = take stem name & add ide .

Get access

Grade+
$40 USD/m
Billed monthly
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers
Class+
$30 USD/m
Billed monthly
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
7 Verified Answers

Related Documents