Biochemistry 2280A Lecture Notes - Lecture 21: Ribosome-Binding Site, Stem-Loop, Operon

28 views22 pages

Document Summary

Second step in central dogma key step in regulation. The genetic code (cid:498)spells(cid:499) out the amino acid sequence in 3 (cid:498)letter(cid:499) (cid:498)words(cid:499) called codons: words are 3 letters in length and there are 4 letters. 20 amino acids = have to code for all 20. Need at least 20 codons = 20 different words. 4 x 4 4 at each position. A one letter code with a u g c = 4 codons. If codons were only 1 base in length, would only have 4 possible codons (aguc: not enough because we have 20 amino acids, not enough. A two letter code would provide: 4x4 = 16 amino acids: less space consuming but doesn"t code for all amino acids. As there are 20 amino acids, a 3 letter code (64 codons) is sufficient. Could have a 4 letter code = wasteful. 3 is the minimum u could have for the fact that we use 20 amino acids.

Get access

Grade+
$40 USD/m
Billed monthly
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers
Class+
$30 USD/m
Billed monthly
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
7 Verified Answers

Related Documents

Related Questions