MATA36H3 Lecture 15: separation

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MATA36H3 Lecture Notes - Lecture 11: Deuterium, Thx, Partial Fraction Decomposition

MATA36H3 Lecture 15: separation

MATA36H3 Lecture 16:

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Ode is an equation that defines ycx ) implicitly , mix x y . derivations of y. Typically , not possible to solve y ex ) Separable equation easiest type of ode fix ) . err some expression with y. Some expression with x g cos cxy: x sin cxy) I side y x on the other side. F view y variable as fix )dx vids t. Ah initial condition could be give such as yw ) C cause we already know the x and in this equation y. T dtc try co solve for y. " n" y e ly , e ? et. D - cxti ) (x - 1) cy - d = dydx i f , dy = I y - y e change this to. X y - i y=cee- ti general solution. Y - xy with ye - d= - i x i. I e i . y=ze - particular solution: cosy dxtclte.

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Can you help solve these problems

Detailed solutions please. I've tried this question 20+ timesand still cannot get the right answer!

Need detailed help/answers/advice.1. A picture framer has a piece of wood that measures one inch wide by 50 inches long. She would like to make a picture frame as shown below, and uses all 50 inches of wood she has. Notice that x and y in our sketch below are the outside dimensions of the frame. The picture looks like a rectangle with the measurements 1 inch around all sides and it says that the length of the rectangle is Y and the width is X. A. Write an equation that expresses the required relationship between variables x, y, and the total length of the wood. I got 2(x+y)=50 B. Solve your equation from part (A) for y in terms of x. Got y=25-x C. Write an expression (i.e. a function) that gives the interior area of the frame as a function of its exterior height x. x^2+25x-50?? Confused on everything from here on out. D. Find the values of x that make the interior area of the picture frame equal to zero. Explain why this is the case in the context of the picture frame problem. Draw the frames that correspond to these two extreme conditions. E. Use your function to find the inside dimensions that will make this area a maximum. State also the maximum internal area of the picture frame. The second part of it goes like this: Now the picture framer would like to rework this problem for a piece of wood of arbitrary length L. [In PART I, L was 50 inches. Now L becomes a new variable so that we can generalize what we did in PART I for a piece of wood of any arbitrary length, L] A. Write an equation that expresses the required relationship between variables x, y, and the total length of the wood L. In PART I, you had a linear equation of the form ax+by = 50 where a and b were numbers. Now you will have a slightly more complicated equation involving x, y and L, i.e. your equation will have three variables, x, y, and L in it. B. Solve your equation from part (A) for y in terms of x and L. C. Use your answer to part (B) to write an expression (i.e. a function) that gives the interior area of the frame as a function of its exterior height x, and the wood length L. [The variable y will not appear in this equation] D. Use your function to find the inside dimensions that will make this area a maximum. Now each of your inside dimensions will depend on L, i.e. they will be functions of L.

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MATA36H3 Lecture 15: separation

MATA36H3 Lecture Notes - Lecture 11: Deuterium, Thx, Partial Fraction Decomposition

MATA36H3 Lecture 15: separation

MATA36H3 Lecture 16:

Document Summary

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