Log in
HomeClass Notes1,200,000CA670,000

MAT102H5 Lecture Notes - Lecture 8: Empty Set

52 views1 pages
Verified Note
eliteobserver
22 Sep 2018
School
UTM
Department
Mathematics
Course
MAT102H5
Professor
Shay Fuchs

For unlimited access to Class Notes, a Class+ subscription is required.

MAT102H5 verified notes
8/38View all
7

MAT102H5 Lecture 7: MAT102Y5 Lecture 7 - Continuation of sets

8

MAT102H5 Lecture Notes - Lecture 8: Empty Set

9

MAT102H5 Lecture 9: Lecture 9 - Functions

Document Summary

Interval notation if (cid:1853),(cid:1854) , with (cid:1853) (cid:1854), then [(cid:1853),(cid:1854)]={ ;a x b} this is a closed interval if (cid:1853),(cid:1854) , with (cid:1853) (cid:1854) , then (cid:4666)(cid:1853),(cid:1854)(cid:4667)={ ;a

Get access

Grade+
$40 USD/m
Billed monthly
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers
Class+
$30 USD/m
Billed monthly
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
7 Verified Answers

Related Documents

MAT102H5
Final Exam
Study Guide
MAT102H5 Study Guide - Midterm Guide: Contraposition, Bounded Function
turquoisegnu128
MAT102H5
Final Exam
Study Guide
MAT102H5 Quiz: MAT 102 quiz 1 practice questions for numbers, sets & functions
pinkshark212
MAT102H5
Final Exam
Study Guide
MAT102H5 Study Guide - Quiz Guide: Joule, Quadratic Equation, Jyj
champagnecaribou11

Related Questions



The number e can be defined as number along the x-axis for which, starting from x =1, the area under the curve y = 1/x from x = 1 to x = e is 1. Partitioning the interval [1,3] into sufficiently small subintervals, approximate the area under the y = 1/x over the interval in a way that allows you to conclude that 2 < e < 3. You will need to use enough subintervals and then do some arithmetic. Familiarity with a famous discrete series can save you time but, strictly speaking, is not needed for the numerical computation. (the problem here is to define e indepedently, in its own right, by only using the function y = 1/x and operations of calculus)