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PHYS 325 Lecture 13: Lecture 13

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graydog965
14 Oct 2019
School
University of Calgary
Department
Physics
Course
PHYS 325
Professor
Micheal Weiser

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

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Related Questions

Speed of the primary wave Vp= 8km/s

Travels time of primary wave =tp
Speed of the secondary waveVs=4.5km/s
Travels time of secondary wave=ts
If d is the distance fromtheearthquaketo the seismograph.
Then
ts=d/Vs
tp=d/Vp
The difference in the arrivaltimes is
78s= ts-tp
Therefore
d/4500 m/s - d/8000 m/s= 78s
d = 8.02x 105 m
= 802 km

I don't under how you calculate d/4500 -d/8000 =78s to get
d = 802km
thanks!!!
B

An object is dropped from rest from a certain height. Air resistance is negligible. After falling a distance d, the object's kinetic energy is proportional to which of the following?

 

(A) 1/d2  (B) 1/d  (C) √d  (D) d 

If you have a concave mirror, how far must you place the object? in order to get an upright, enlarged image?

d= distance from the object to mirror; f=mirror's focal length

d < f

d = f

d > f

d > 2f

more information is needed