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PHYS 325 Lecture 16: Lecture 16

Canada

Modern Physics

Physics

Micheal Weiser

University of Calgary

<p>Speed of the primary wave V<sub>p</sub>= 8km/s</p> <div> Travels time of primary wave =t<sub>p</sub> </div> <div> Speed of the secondary waveV<sub>s</sub>=4.5km/s </div> <div> Travels time of secondary wave=t<sub>s</sub> </div> <div> If <em>d</em> is the distance fromtheearthquaketo the seismograph.</div> <div> Then</div> <div> t<sub>s</sub>=d/V<sub>s</sub> </div> <div> t<sub>p</sub>=d/V<sub>p</sub><div> The difference in the arrivaltimes is</div> </div> <div> 78s= t<sub>s</sub>-t<sub>p</sub> </div> <div> Therefore</div> <div> d/4500 m/s - d/8000 m/s= 78s</div> <div> d = 8.02x 10<sup>5</sup> m</div> <div> = 802 km</div> <div><br></div> <div>I don't under how you calculate d/4500 -d/8000 =78s to get</div> <div>d = 802km</div> <div>thanks!!!</div> <div>B</div>

<p>An object is dropped from rest from a certain height. Air resistance is negligible. After falling a distance d, the object's kinetic energy is proportional to which of the following?</p>
<p> </p>
<p>(A) 1/d2  (B) 1/d  (C) √d  (D) d </p>

<p>If you have a concave mirror, how far must you place the object? in order to get an upright, enlarged image?</p>
<p>d= distance from the object to mirror; f=mirror's focal length</p>
<p>d &lt; f</p>
<p>d = f</p>
<p>d &gt; f</p>
<p>d &gt; 2f</p>
<p>more information is needed</p>
<p>&nbsp;</p>

PHYS 325 Lecture 16: Lecture 16

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