COMD 2050 Chapter : Chapter 1 Origins Of Language
Document Summary
Chapter 14 review: a rooster with gray feathers is mated with a hen of the same phenotype. Among their offspring, 15 chicks are gray, 6 are black, and 8 are white. First was homozygous, second was heterozygous: a black guinea pig crossed with an albino guinea pig produced 12 black offspring. When the albino was crossed with a second black one, 7 blacks and 5 albinos were obtained. What is the best explanation for this genetic situation: phenylketonuria (pku) is an inherited disease caused by a recessive allele. Pp x pp: all three of their children will be of normal phenotype. 37/64: one or more of the three children will have the disease (1-a) a + b = 1, all three children will have the disease. X x : at least one child will be phenotypically normal (1-c) c + d = 1. 1/64: a man has six fingers on each hand and six toes on each foot.
