PHY 2049 Final: University of Florida PHY 2049 phy2049_s08_final_practice
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Note that each problem has three versions, each with di erent numbers and answers (separated by | ). 6 neutrons) with a velocity of (32, 000 | 37, 000 | 42, 000) km/s. What is the radius of its orbit (note that 1 fm = 10 15 m. ) Answer: 53. 8 fm | 34. 1 fm | 22. 9 fm. Solution: for circular motion the magnitude of the force is |f| = mv2/r. Also, by coulomb"s law the magnitude of the force is |f| = k(2e)(6e)/r2. Setting these two forces equal, the radius of the orbit is r = k(2e)(6e)/(mv2): an electron moves rightward between two parallel charged plates separated by distance d = 52 cm as shown in the gure. Answer: 1460 km/s | 1720 km/s | 1970 km/s. Solution: using conservation of energy, unknown in this equation. Solution: let i1 be the current going clockwise in the left loop, and let i2 be the current going counterclockwise in the right loop.
