CHEM 153A Quiz: W18 Week 5 SQ Part II Answers
9 Jan 2019
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Part ii: on each of the following plots, indicate what you would expect to observe if you performed kinetic analysis using one-half the indicated amount of enzyme: The reaction is at initial velocity (there is no product or back reaction to consider). 0. 25vmax = vmax[4]/km + [4]; solve for km = 12 mm: an enzyme exhibiting michaelis-menton kinetics has a velocity of 0. 2 vmax at a substrate concentration of 1. 0 mm. 0. 2vmax = vmax[1 mm]/km + [1mm]; solve for km = 4 mm. 0. 6vmax = vmax[s]/4 mm + [s]; solve for [s]= 6 mm: you assay 0. 002 nm of enzyme x at two different substrate concentrations in the presence and absence of an inhibitor, with the following results: [substrate] ( m) nm product after 20 sec of reaction nm product after 20 sec of reaction. 133. 33/20 = 6. 667 1/6. 67 = 0. 15 without inhibitor with 2 mm inhibitor. 50/20 = 2. 5 1/2. 5 = 0. 4: construct a lineweaver-burke plot of the data.
