MATH 214 Midterm: MATH214_ALL-SECTIONS_SPRING2014_0000_MID_SOL_1

• School: University of Maryland
• Department: Mathematics
• Course: MATH 214
• Professor: All

Document Summary

Math 214 spring 2014 exam 2 solutions: a) spinner 1. 4 the grid is so much easier to type up! 2: s = {0, 1, 2, 3, 4, 5} difference. 1/15: ev = 0(2/15) + 1(4/15) + 2(4/15) + 3(2/15) + 4(2/15) + 5(1/15) = 31/15 or 2. 067, no, not independent. P(b | a) = 1/10 but p(b) = 2/15. Or, p(a | b) = 1/2 but p(a) = 2/3. Or, p(a)p(b) = (2/3)(2/15) = 4/45 but p(a and b) = 1/15: yes they are mutually exclusive. It is impossible to get a difference of 0 when the first spinner shows 3: a) (5/8)(4/7)(3/6) = . 179, 8!/(3!2!) = 3360: 1 - (3/8)(2/7)(1/6) = . 982, a) 7c3 = 35, 25/35 = . 714 or 5/7, combos that do not contain either: 5c3 = 10. So 35 - 10 = 25 combos that do: a) 1 - . 69 = . 31.