MATH 220 Midterm: MATH 220 TAMU 220-Fall 03 Exam 3Solutions
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Exam #3 solutions: this problem did not cause too much trouble, so i won"t draw the graphic for it. 3 , 2] [ 1 i , 2] . For (b) the intersection is just the rst interval, because each interval is contained in the next and [1, 2] is the smallest one, so the answer is [1, 2]: proceed as follows: A (a b) = a a b. = (a a) (a b) C a b: let c c be arbitrary. Because c c, we have h(c) = 0. By the de nition of h then, h(c) = f (c) g(c) = 0, which implies that f (c) = 0 or g(c) = 0. If f (c) = 0, then c a by the de nition of a. If g(c) = 0, then c b by the de nition of b. Thus, c a or c b, and so c a b.
