MATH 0120 Midterm: MAT-120 answers-2.6-364
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4 (cid:19), x-intercepts: ( 3, 0) and (2, 0: vertex=(cid:18) , vertex=(cid:18) 5. 4(cid:19), x-intercepts: (3, 0) and (2, 0: vertex=(0, 16), x-intercepts: ( 4, 0) and (4, 0, vertex=(cid:18) 8. , 0(cid:19) and (4, 0: vertex=( 1. 5, 3. 3), x-intercepts: ( 3, 0) and (cid:18)1, solve x2 + 4 = x + 2. Which is: x2 + x 2 = 0. Factor and x = 2, x = 1: solve x2 + 2x + 6 = x2 6. Which is: 2x2 2x 12 = 0. Divide by 2 and factor. x = 3, x = 2: solve 2x2 5x 8 = 3x2 + x + 5. Which is: 5x2 6x 13 = 0. 5: ssubstitute x = 2p2 + p 10 into 11p + 3x 66 = 0 and get: 6p2 + 14p 96 = 0. Which is: 3p2 + 7p 48 = 0. Factor and the equilibrium price is p = 3.
