MATH 1550 : Calc Final Review

12 views6 pages

azuremammoth471

15 Mar 2019

School

Department

Course

Professor

For unlimited access to Study Guides, a Grade+ subscription is required.

Document Summary

Math 1550, review for final: evaluate each limit. If the limit does not exist, justify your answer. sin (a) lim x. 2 find all values of k so that the following function is continuous everywhere. f x. 1: use the precise definition of the derivative to find f x for the function f x ( ) 5. 1: find the derivative of each function. (do not simplify) 1 cot 2 x cos x (a) f x (b) f x. 5] at what points on the graph of: find the interval(s) on which the function f x tan. 7 find point(s) of inflection on the curve f x x x. 8 a package delivery service can only accept an overnight package if its length plus width plus height sums to 40 inches. Find the: the population of the world is predicted to be number of years after 2000.

Related Questions

3. (21 pts) Evaluate the limit or say that the limit does not exist. If a limit does not exist, explain why. Show your work. You may NOT use a table of values, a graph, or L'Hospitals's Rule to justify your answer. (Note: Possible answers include + or -..) (a) (7 pts) x2 - 2x - 3 - lim x+3 Vx+1 - 2 x2 - 2x - 3 Vx+ 1 + 2 lim x+3 Vx+1 -2 Vx+1 +2 (x - 3) (x + 1) (Vx+ = lim x+3 x + 1 - 4 = lim x+3 (x - 3) (x + 1) (Vx+1 +2). -- x-3 = lin (x + 1) (Vx+1 +2) = (3 + 2) (V3+1 +2) = = 4 (V4 +2) = 16 (b) (7 pts) lim xsin (In x) X >0+ NOTE: We cannot apply the Product Law, since lim sin (1n x) DOES NOT EXIST. On the other hand, -1s sin (in x) s 1 and , therefore, -xs x sin (in x) sx, (since x > 0). Since lim X = lim (-X) = 0, x0+ X0 the inequality above implies that lim xsin (in x) = 0, by the Squeeze Theorem . x0+ EXPLANATION : Since lim ln x = -0, x →0+ sin (lnx) oscillates between 1 and -1 as x + 0*, and, therefore lim sin (In x) DOES NOT EXIST. x >0+ (c) (7 pts) in x+2- (lnx) +In 20 -= -00 (x - 2) 70-