MATH 205 Final: MATH 205 KSU Final Exam f00
15 Feb 2019
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Point values for individual questions are given in parentheses following the question number. If you use space outside that provided for a problem (e. g. the back of another page) leave instructions in the space provided where the additional work is to be found. Otherwise it will not be considered for partial credit. For each question on this page nd the indicated de nite or inde nite integral: (8, (8, (8, (8) 1 = (64 16 + 4) (1 1 + 1) = 51. 0 = eln 5 e0 = 5 1 = 4. = 4 2 4 1 = 4. 1 f (x)dx (b) in your ordered list above, circle all the intergrals with negative values. (c) estimate. It is about . 3, since counting the little 1/4 by 1/4 blocks, it comes out a little less than 5 of them, meaning a little less than 5/16 = . 3125.
