CHEM 1021 Study Guide - Final Guide: Iron(Ii) Oxide, Copper Sulfide, Molar Mass
Final Review
Chemistry 1021
Roman numerals: ionic compounds
• Transition metals
• Plus, metals in main groups under stair steps (not Al)
No Roman numerals
• 1st two groups, plus Al
When do you use a Roman numeral in the name of a compound?
Which of the following formula/name pairs is incorrect?
A. K2SO4 – potassium sulfate
B. Na3N – sodium nitride
C. Li2CO3 – lithium carbonate
D. Fe2O3 – iron (II) oxide
E. Cu2S – copper sulfide
Should be Fe (III) oxide
Naming Molecular Compounds
NO2 – nitrogen dioxide
Tetra phosphorous hexaoxide – P4O6
Naming Acids
Which of the following formula/name combinations is incorrect?
A. HNO2 (aq) – nitrous acid
B. HBr (aq) – hydrobromic acid
C. H2SO3 (aq) – sulfurous acid
D. HClO2 (aq) – hypochlorous acid
E. H3PO4 (aq) – phosphoric acid
Should be: chlorous acid
Mass Percent
• Find the mass percent of silicon and oxygen in quartz (SiO2).
o Molar mass: 28.09 + 2(16.00) = 60.09 g/mol
o Mass of Si: (28.09g)/(60.09g)x100 = 46.75 %
o Mass of O2: 100 – 46.75 = 53.258 %
• How many grams of silicon are present in 2348 g of quartz?
o (348g)x[(46.75)/(100)] = 163 g Si
Empirical Formulas
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Document Summary
Roman numerals: ionic compounds: transition metals, plus, metals in main groups under stair steps (not al) No roman numerals: 1st two groups, plus al. Which of the following formula/name pairs is incorrect: k2so4 potassium sulfate, na3n sodium nitride, li2co3 lithium carbonate, fe2o3 iron (ii) oxide, cu2s copper sulfide. Which of the following formula/name combinations is incorrect: hno2 (aq) nitrous acid, hbr (aq) hydrobromic acid, h2so3 (aq) sulfurous acid, hclo2 (aq) hypochlorous acid, h3po4 (aq) phosphoric acid. Empirical formulas: methyl butyrate is a compound that is partially responsible for the flavor of apples. To find molecular formula: empirical formula find molar mass, molar mass/empirical formula molar mass = whole number. Iron metal (55. 85 g/mol) reacts with chlorine gas (70. 9 g/mol) according to the equation: 2fe (s) + 3cl2 (g) 2fecl3 (s) If 25. 6 g each of iron and chorine react, how much fecl3 (162. 35 g/mol) will be formed: fe: (25. 6g fe)(1molfe/55. 85gfe)(2molfecl3/2molfe)(162. 35gfecl3/1molfecl3) = 74. 4 g.
