APPM 1360 Midterm: appm1360fall2014exam1_sol

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31 Jan 2019
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1 ln(t 1) dt (b) (10 pts)z ex sin x dx (c) (10 pts)z. 1 x 4x2 + 16 dx (d) (12 pts) verify the integration formula shown by integrating the left side of the equation and showing that it equals the right side: Solution: (a) this is an improper integral since ln(t 1) is unde ned at t = 1. Then du = dt/(t 1) and v = t. a u dt ln(t 1) = lim a 1+ ( a ln(a 1) [2 + ln(1) a ln(a 1)]) ( a ln(a 1) 2 + a + ln(a 1)) ( a ln(a 1) + ln(a 1)) = 2 + 1 + lim a 1+ (1 a) ln(a 1) Z ex sin x dx = ex cos x +z cos x ex dx. U = ex du = ex dx dv = cos x dx.

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