PHY 121 Midterm: PHY121 Exam 1 Spring 2014

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31 Jan 2019
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A bowling ball is placed on a scale in an elevator that is accelerating upward at a rate of a. The scale displays a value of 90 n. on the next ascent, the elevator accelerates for a short time at twice the original rate, 2a. This bowling ball is removed from the elevator and then hung suspended from the middle of a string. 6/6 m = 90/(10+10/8) m = 8 kg. Fup = fdown sin fleft + sin fright = mg. 2 sin fleft = m g (fleft = fright) A point guard makes a bounce pass to the center. The basketball is thrown with an initial speed of 10. 0 m/s at an angle of 30 below the horizontal. It is released 1. 00 m above the floor. What horizontal distance does the ball cover before bouncing? y = at2 + vo_y t + yo. 1 = 5t2 + sin30 10 t + 0 down is positive.

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