MAT-2130 Midterm: MATH 2130 App State Fall2011 Test3

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15 Feb 2019
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Be sure to show your work! x = cos( ) sin( ) y = sin( ) sin( ) z = 2 (1 + cos(2 ): (15 points) consider z 2. Sketch the region of integration and then evaluate the integral. Hint: r ey2 dy is impossible to evaluate. Reading o the bounds on the iterated integral, the region of integration is bounded by y = x/2, y = 1, x = 0, and x = 2. Since the antiderivative of ey2 is not something we are familiar with, we need to reverse the order of integration to nd the answer. Notice that (as a type ii) region the bounds are: 0 x 2y and 0 y 1. Z 2 x/2 ey2 dy dx = z 1. Change coordinates using u = 3x y and v = x + y. R da where r is bounded by y = 3x + 1, y = 3x + 2, y = x, and.

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