BIOC2000 Study Guide - Final Guide: Glucokinase, Hexokinase

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5 Jun 2018
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Tuesday, 5 June, 2018
Michaelis Menten Equation
[E]+[S] <-> [ES] -> [E]+[P]
-Derive Mentens Equation from Vo Vmax and Km using steady sate assumption
-K1 K-1 K2; assume no k-2
-Km=rate of disassociation/rate of association = k-1+ k2/ k1
-steady state assumption equation k1 ([E]+[S]) =k-1 [ES] + k2 [ES]
-E Total = E binding to ES + free enzyme E
-free enzyme E = E Total -E binding to ES (a)
-sub (a) into the assumption equation k1 ([E]+[S]) =k-1 [ES] + k2 [ES]
-k1 ([E Total -E binding to ES]+[S]) =k-1 [ES] + k2 [ES]
-Do the factorisation
-k1(E Total)[S]-k1(E binding to ES][S] = (k-1 + k2)[ES] (b)
-divide (b) by k1 to get Km formula in the equation
-k1(E Total)[S]-k1(E binding to ES][S] /k1 = (k-1 + k2)[ES]/1
-(E Total)[S]-(E binding to ES][S] = Km[ES]
-Done with substituting Km, Vo and Vmax left
-Since Vo= k2[ES], we want to try substituting Vo in equation by getting [ES] by
itself
-(E Total)[S]= Km[ES] +[E binding to ES][S]
-By doing factorisation,
-(E Total)[S]=[ES](Km+[S] )
-[ES]=(E Total)[S]/(Km+[S] ) (c)
-Sub Vo in (c)
-Vo/k2 = (E Total)[S]/(Km+[S] ) (d)
-get rid of k2 on the left side to fit Vmax in
-Vo/k2 x k2= (E Total)[S]/(Km+[S] ) x k2
-Vo= (E Total)[S] k2 /(Km+[S] ) (e)
-Done with substituting Km and Vo, Vmax left
-assume all enzymes saturated at Vmax; no free enzymes left so E Total = [ES] (from E
Total = E binding to ES + free enzyme E)
-Assume ES = E total
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Document Summary

Derive mentens equation from vo vmax and km using steady sate assumption. Km=rate of disassociation/rate of association = k-1+ k2/ k1. Steady state assumption equation k1 ([e]+[s]) =k-1 [es] + k2 [es] E total = e binding to es + free enzyme e. Free enzyme e = e total -e binding to es (a) Sub (a) into the assumption equation k1 ([e]+[s]) =k-1 [es] + k2 [es] K1 ([e total -e binding to es]+[s]) =k-1 [es] + k2 [es] K1(e total)[s]-k1(e binding to es][s] = (k-1 + k2)[es] (b) Divide (b) by k1 to get km formula in the equation. K1(e total)[s]-k1(e binding to es][s] /k1 = (k-1 + k2)[es]/1. (e total)[s]-(e binding to es][s] = km[es] Done with substituting km, vo and vmax left. Since vo= k2[es], we want to try substituting vo in equation by getting [es] by itself. (e total)[s]= km[es] +[e binding to es][s] Get rid of k2 on the left side to t vmax in.

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