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29 Nov 2021
Problem 70a
Page 773
Section: Cumulative Problems
Chapter 18: Electrochemistry
Textbook ExpertVerified Tutor
29 Nov 2021
Given information
half-cells,
Volume of each half-cell is , and the concentrations of Ag+ in the half-cells are and
Step-by-step explanation
Step 1.
The number of moles of Ag+ at cathode is calculated by:
Where,
- is the concentration of Ag+ at cathode.
- is the volume of half cell.
Putting the values in the above-mentioned equation
Similarly, The number of moles of Ag+ at anode is calculated by:
Let the change in the number of moles of Ag+ at anode and cathode be
Therefore the final no. of moles of Ag+ at anode is
and the final no. of moles of Ag+ at cathode is
The number of moles of Ag+ at anode and Ag+ at cathode becomes equal when the battery dies.
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