1
answer
183
views
70a
Problem

For access to Textbook Solutions, a Class+ or Grade+ subscription is required.

Textbook Expert
Textbook ExpertVerified Tutor
29 Nov 2021

Given information

half-cells,
Volume of each half-cell is , and the concentrations of Ag+ in the half-cells are   and
 

Step-by-step explanation

Step 1.

The number of moles of Ag+ at cathode is calculated by:

 

Where,

  • is the concentration of Ag+ at cathode.
  •  is the volume of half cell.

Putting the values in the above-mentioned equation

 

 

Similarly, The number of moles of Ag+ at anode is calculated by:

 

   

 

Let the change in the number of moles of Ag+ at anode and cathode be  

Therefore the final no. of moles of Ag+ at anode is

 

and the final no. of moles of Ag+ at cathode is

 

The number of moles of  Ag+ at anode and Ag+ at cathode becomes equal when the battery dies.

 

 

 

Unlock all Textbook Solutions

Already have an account? Log in
Start filling in the gaps now
Log in