Textbook ExpertVerified Tutor
23 Nov 2021
Given information
(1-√3i)^5
Step-by-step explanation
Step 1.
De moivre's theorem,
(cos y + i sin y)^n= cos ny + i sin ny
Now,
z= (1-√3i)^5= (e(cos√3 + i sin√3))^5
=e^5(cos5√3 + i sin5√3)
(1-√3i)^5
De moivre's theorem,
(cos y + i sin y)^n= cos ny + i sin ny
Now,
z= (1-√3i)^5= (e(cos√3 + i sin√3))^5
=e^5(cos5√3 + i sin5√3)