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Some states now allow online gambling. As a marketing manager for a casino, you nised to determine the percentage of adults in those states who gamble online. How many adults must you survey in order to be 95% corfident that your estimate is in error by no more than one percentage point? Complete parts (a) and (b) below.

a. Assume that nothing is known about the paroanitage of adults who gamble ori neR

(Round up to the nearest integer.)

b. Assume that 18% of all adults gamble online.

naB

(Round up to the nearest integer.)

Question 12 of 14

Archeologists have studied sizes of Egyptian skulls in an attempt to determine whether breeding occurred between different cultures. Listed below are the widths (mm) of skulls from 150 A.D. Construct a 90% confidence Interval estimate of the mean skull width

127.7    138.1    126.4    131.9    143.4    134.9    138.6    128.7 

____ mm < < mm ____ 

(Round to two decimal places as needed.)

Which of the following is NOT a property of the Student t distribution?

Choose the correct answer below.

O A. The Student t distribution has a mean of t= 0.

O B. The Student t distribution has the same general symmetric bell shape as the standard normal distribution, but it reflects the greater variability that is expected with

small samples.

• C. The Student t distribution is different for different sample sizes.

O D. The standard deviation of the Student t distribution is s = 1

Question 14 of 14

Find the sample size needed to estimate the mean age of movie patrons such that it can be sold with 90% confidence that the sample mean Is within 2.5 years of the

population mean. Assume that a = 19.5 years, based on a previous report. Should the sample be obtained from one movie at one theater?

The required sample size is ____. (Round up to the nearest integer.)

Should the sample be obtained from one movie at one theater?

A. The sample should not be obtained from one movie at one theater, because that sample could be easily biased. Instead, a stratified sample of the broader population should be obtained.

B. The sample should not be obtained from one movie at one theater, because that sample could be easily blased. Instead, a simple random sample of the broader

population should be obtained.

C. The sample should be obtained from one movie at one theater, because that sample is representative of the population.

D. The sample should not be obtained from one movie at one theater, because that sample could be easily biased. Instead, a cluster sample of the broader population should be obtained.

Here are summary statistics for randomly selected weights of newborn girls: n = 36, x = 3222.2 g, s = 686.7 g. Use a confidence level of 99% to complete parts (a)

through (d) below.

a. Identify the critical value ta/2 used for finding the margin of error.

4/2=0

(Round to two decimal places as needed.)

b. Find the margin of error.

E= 0 g

(Round to one decimal place as needed.)

c. Find the confidence interval estimate of p.

(Round to one decimal place as needed.)

d. Write a brief statement that interprets the confidence interval. Choose the correct answer below.

Question 8 of 14

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Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. The results in the screen display are based on a 95% confidence level. Write a statement that correctly Interprets the confidence interval.

Tinterval

(13.046,22.15)

x= 17.598

Sx= 16.01712719

n = 50

Choose the correct answer below.

O A. We have 95% confidence that the limits of 13.05 Mbps and 22.15 Mbps contain the true value of the mean of the population of all data speeds at the airports

O B. The limits of 13.05 Mbps and 22.15 Mbps contain 95% of all of the data speeds at the airports.

O C. We have 95% confidence that the limits of 13.05 Mbps and 22.15 Mbps contain the sample mean of the data speeds at the airports.

O D. The limits of 13.05 Mbps and 22.15 Mbps contain the true value of the mean of the population of all data speeds at the airports.

く

Question 9 of 14

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In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in ma/dL) have a mean of 5.2 and a standard deviation of 16.5. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol?

Click here to view at distribution table.

Click here to view page 1 of the standard normal distribution table.

Click here to view page 2 of the standard normal distribution table.

What is the confidence interval estimate of the population mean u?

mg/dL <p< ma/dL

(Round to two decimal places as needed.)

What does the confidence interval suggest about the effectiveness of the treatment?

A.. The confidence interval limits contain 0, suggesting that the garlic treatment did affect the LDL cholesterol levels.

B. The confidence interval limits do not contain 0, suggesting that the garlic treatment did affect the LDL cholesterol levels.

O C. The confidence interval limits do not contain 0, suggesting that the garlic treatment did not affect the LDL cholesterol levels.

• D. The confidence interval limits contain 0, suggesting that the garlic treatment did not affect the LDL cholesterol levels.

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A random sample of 857 births In a state Included 425 boys. Construct a 95% confidence interval estimate of the proportion of boys in all births. It is believed that among all births, the proportion of boys is 0.509. Do these sample results provide strong evidence against that belief?

Construct a 95% confidence interval estimate of the proportion of boys in all births.

<p< (Round to three decimal places as needed.)

Do these sample results provide strong evidence against that belief?

A. There is strong evidence against 0.509 as the value of the proportion of boys in all births because 0.509 is contained within the 95% confidence interval.

B. There is not strong evidence against 0.509 as the value of the proportion of boys in all births because 0.509 is not contained within the 95% confidence interval.

C. There is strong evidence against 0.509 as the value of the proportion of boys in all births because 0.509 is not contained within the 95% confidence interval.

D. There is not strong evidence against 0.509 as the value of the proportion of boys in all births because 0.509 is contained within the 95% confidence interval.

Use the sample data and confidence level given below to complete parts (a) through (d).

A drug is used to help prevent blood clots in certain patients. In clinical trials, among 4755 patients treated with the drug, 134 developed the adverse reaction of nausea.

Construct a 90% confidence Interval for the proportion of adverse reactions.

a Find the best point estimate of the population proportion p.

(Round to three decimal places as needed.)

b) Identify the value of the margin of error E.

(Round to three decimal places as needed.)

c) Construct the confidence interval.

<0<

(Round to three decimal places as needed.)

d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.

O A. 90% of sample proportions will fall between the lower bound and the upper bound.

• B. One has 90% confidence that the sample proportion is equal to the population proportion.

O C. One has 90% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.

• D. There is a 90% chance that the true value of the population proportion will fall between the lower bound and the upper bound

The overhead reach distances of adult females are normally distributed with a mean of 205.5 cm and a standard deviation of 8.9 cm.

Find the probability that an individual distance is greater than 215.50 cm.

Find the probability that the mean for 20 randomly selected distances Is greater than 204.00 cm.

Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

a. The probability is

(Round to four decimal places as needed.)

b. The probability is

(Round to four decimal places as needed.)

c. Choose the correct answer below.

O A. The normal distribution can be used because thI original population has a normal distribution.

B. The normal distribution can be used because the probability is less than 0.5

C. The normal distribution can be used because the mean is large.

D. The normal distribution can be used because the finite population correction factor is small.

I

Assume that the amounts or weght that male collece students gain dunng their res

o = 5.6 kg. Complete parts (a) through (c) below.

Jazlyn Marichal 04/26/23 1:27 PM

©

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man vear are normally distributed with a mean or ue 1 kg and a standard deviation of

tion list

stion 4

ion 5

n 6

7

a. If 1 male college student is randomly selected. find the probability that he gains between 0 kg and 3 kg during freshman year.

The probability is

(Round to four decimal blaces as needed.

o. If g male college students a re randomly selected. find the probabiliry that their mean weight gain durng ireshman vear is between O kg and 3 kc

The probability is M

(Round to four decimal places as needed.

c. Why can the normal distribution be used in part (b). even though the sample size does not exceed 30?

AS A. Since the distribution is of sample means, not individuals, the distribution is a normal distribution for any sample size.

О в.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

C. Since the weight gain exceeds 30, the distribution of sample means is a normal distribution for any sample size

• D. Since the distribution is of individuals, not sample means, the distribution is a normal distribution for any sample size.

Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1.

@

06

2=-0.99

The area of the shaded region is

(Round to four decimal places as needed.)

The weights of the chocolate in Hershey Kisses are normally distributed with a mean of 4.5338 g and a standard deviation of 0.1039 g.

For the bell-shaped graph of the normal distribution of weights of Hershey Kisses, what Is the area under the curve?

What is the value of the median?

What is the value of the mode?

What is the value of the variance?

For the bell-shaped graph of the normal distribution of weights of Hershey Kisses, what is the area under the curve?
(Type an integer or a decimal. Do not round.)

What is the value of the median?
g (Round to four decimal places as needed.)

What is the value of the mode?
g (Round to four decimal places as needed.)

What is the value of the variance?
9? (Round to four decimal places as needed.)

the Indicated z score. The graph depicts the standard normal distribution with mean 0 and standard deviation 1.

@

0.1446

The indicated z score is

(Round to two decimal places as needed.)

Question 12 of 16

Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score Is less than - 1.54 and draw a sketch of the region.

Sketch the region. Choose the correct graph below.

The probability is ____.

(Round to four decimal places as needed.)

Question 13 of 16

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Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15.

Click to vlew page 1 of the table. Click to vlew page 2 of the table.

85

110

The area of the shaded region is

• (Round to four decimal places as needed.)

in the blank.

The

SISTESTINATIOR O PARISSAR with any distribution. the distribution of the samole means aproaches a normal distribution as the sample size increase:

The

tells us that for a population with any distribution, the distribution of the sample means approaches a normal distribution

as the sample size increases

K

Question 15 of 16

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Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P17, the 17th percentile. This Is the bone density score separating the bottom 17% from the top 83%.

Which graph represents P17? Choose the correct graph below.

O A.

О в.

O c

@

Q

O D.

@

P17

The bone density score corresponding to P17 is (Round to two decimal places as needed.)

P17

P

P47

ム

4

Question 16 of 16

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Assume that adults have IQ scores that are normally distributed with a mean of 99.2 and a standard deviation 21.9. Find the first quartile Q4, which is the IQ score separating the bottom 25% from the top 75%. (Hint Draw a graph.)

The first quartile is

(ype an Integer or decimal rounded to one decimal place as needed.)

Assume that the amounts of weight that male college students gain during their freshman year are normally distributed with a mean of u = 1.1 kg and a standard deviation of = 5.1 kg. Complete parts (a) through (c) below.

a. If 1 male college student is randomly selected, find the probability that he gains between 0 kg and 3 kg during freshman year.

The probability is ____. Round to four decimal places as needed.

b. If 4 male college students are randomly selected, find the probability that their mean weight gain during freshman year is between 0 kg and 3 kg.

The probability is ____. (Round to four decimal places as needed.)

c. Why can the normal distribution be used in part (b) even though the sample size does not exceed 30?

◯ A. Since the original population has a normal distribution. the distribution of sample means is a normal distribution for any sample size

◯ B. Since the distribution is of sample means, not individuals, the distribution is a normal distribution for any sample size.

◯ C. Since the weight gain exceeds 30, the distribution of sample means is a normal distribution for any sample size.

◯ D. Since the distribution is of individuals, not sample means, the distribution is a normal distribution for any sample size.

Forthefunctionf(x)=2x3 -x+4,
a. At what point(s) would the graph of f(x) have horizontal tangent lines? (You may give the
coordinate(s) as decimals if you wish).
b. On what intervals is the graph of f(x) sloping upward? Sloping downward?
c. On what intervals is the graph of f(x) concave up? Concave down?

1. Determine which ordered pair is a solution to the following system of equations and which are not by checking them with each equation in the system.

1. Which of the following is true about the ordered pair (-1.2, 4.8) with respect to the system of equations below.

(4x-2)*6(2x+7)

Solve the following system of equations by using substitution.

f (x)=3x-4/7 find f-1(x)

Find f. f ''(theta) = sin theta + cos theta, f(0) = 2, f '(0) =2

Find f(theta)

In each of the following problems draw a right triangle for each problem then substitute values and solve.

1. A suitcase measures 22 inches long and 16 inches high. What is the diagonal length of the suitcase to the nearest foot?

2. A right triangle has a hypotenuse of 25 and a leg of 7. What is the measure of the other leg?

3. Two joggers run 6 miles north then 9 miles west. What is the shortest distance to the nearest mile that they must travel to return to the starting point?

4. A 104-foot ladder is leaned against a wall. If the base of the ladder is 40 ft from the wall, how up the wall will the ladder reach?

5. To avoid the pong Fred must walk 10 meters south and 24 meters east> To the nearest meter, how many meters would be saved if it were possible to walk through the pond?

6. A triangle has a width of 15 inches and a diagonal of 17 inches. Find the length of the rectangle in inches.

7. Slanted sides of a tent are 11 feet long each and the bottom of the tent is 12 feet across. What is the tallest point of the tent?

8. A 12-foot pole casts a shadow of 16 feet. What is the distance between the end of the shadow and the top of the pole?

9. Harold rides his bike 33 km south and then 56 km west. How far is the shortest distance from his starting point?

Find a vector g⃗ g→ so that if F{f⃗ }=(c0, c1, c2, c3)F{f→}=(c0, c1, c2, c3) then F{f⃗ ⊛g⃗ }=(3c0,c1,2c2,c3)F{f→⊛g→}=(3c0,c1,2c2,c3).

An aquarium 8 m long, 3 m wide, and 4 m deep is full of water. Findthe following:
the hydrostatic pressure on the bottom of the aquarium ,
the hydrostatic force on the bottom of the aquarium ,
the hydrostatic force on one end of the aquarium

An aquarium 8 m long, 3 m wide, and 4 m deep is full of water. Findthe following:
the hydrostatic pressure on the bottom of the aquarium ,
the hydrostatic force on the bottom of the aquarium ,
the hydrostatic force on one end of the aquarium

An aquarium 8 m long, 2 m wide and 3 m deep is full of water. Findthe work needed to pump half of the water out of theaquarium?
(The acceleration due to gravity is 9.8 and the density of water is1000 .)
note: show me how u did it, please?

3x + 3y + z = 22x + z = 6 4y - 3z = 8