durgeshrathore6232

If we do things right, there is nothing to fix. Discuss this statement in relation to the cost of quality where prevention, appraisal, internal failure and external failure constitute cost of quality. How does this align with the philosophical stance of Philip Crosby?

Anhydrate = MgSO4(s)

Mass of container = 21.400g

Mass of container and content before heating = 26.65g

Mass of hydrate = 5.250

Mass of container and content after heating = 23.960g

Mass of anhydrate = 2.56g

Mass of water lost = 2.69g

Calculate moles of anhydrate in sample 2.56g anhydrate*1mole anhydrate/120.3626 molar mass= 0.0213 moles of anhydrate.

Calculate the ratio of moles of water for 1 mole of anhydrate: 0.149 calculated moles of H2O/0.0213 calculated moles of anyhydrate = 6.995305164/1mole anhydrate = 7 moles H2O/1 mole MgSO4

Use the whole number values calculated in above problem to write the formula for the hydrate =MgSO4(s0*7H2O (g)

Write and equation for the dehydration of the hydrate= MgSO4(s)*7H2O(g) MgSO4 (s) + 7H2O(g)

Write an equation for the dehydration of the following hydrates;

CaCl2*2H2O CaCl2*2H2O CaCl2 +2H2O

CoCl2*6H2O CoCl2*6H2O CoCl2 + 6H2O

Na2CO3*10H2O Na2CO3H2O Na2CO3H2O + 9H2O

Calculate the % water for the hydrate, Na2CO3*10H2O

10 *18/ 286 *100% =63% H2O in Na2CO3*10H2O

If you did not heat the hydrate sample sufficiently to drive off all of the water, would the % of water calculated be too high or too low? Explain.

Aluminum and oxygen gas react to produce aluminum oxide. What is the % of oxygen in the product aluminum oxide?

Answer = 89%

Write a balanced equation for the reaction = 4Al + 6O2 2Al2O3

If 75g of oxygen react, how many grams of Aluminum are required?

How many grams of aluminum oxide can be produced form 75g of oxygen?

You have a 1.25 g sample of a hydrate of Na₂CO₃. By heating the compound, you drive off the water and are left with 0.7403 g of the anhydrous compound, which statement below is correct

A.

mass of water = 0.7403 g

% of Na₂CO₃ = 40.80%

B.

mass of water = 0.510 g

% of Na₂CO₃ = 59.22%

C.

mass of water = 0.7403 g

% of Na₂CO₃ = 59.22%

D.

mass of water = 1.99 g

% of Na₂CO₃ = 37.2%

E.

mass of water = 0.510 g

% of Na₂CO₃ = 40.80%

2) Convert 2.50 mol of Na2CO3 to mass in g.

Find the solution to the following DE’s

(a) dy/dx= x^7/3+x^3/2-2x^2+3

(b) dy/dx= e^5x+ln(x)

(c)dy/dx -2y= X

At x=1: ∫2x dx = 12 + C. At x=2: ∫2x dx = 22 + C.

What is the specific heat (J/kg-K) of a 322.7 g substance that has a temperature change of 24.33 °C and a heat of 28.22 J?

A. Find the amount of heat that must be extracted from 1kgofsteam at a temperature of 110°C in order to convert all ofit to iceat 0°C. What speed would this correspond to ifthis amount ofthermal energy were equal to translational kineticenergy for thegiven mass?

B. A 50g ice cube is added to 110g of water in a 62galuminumcup. The water and cup initially have a temperatureof 23°C. Findthe initial temperature of the ice cubesuch that all of the wateris just turned to ice. Use thefollowing specific heats: water =4186 J/(kg·K), ice = 2090J/(kg·K), and aluminum = 900 J/(kg·K).Thelatent heat of fusion for water is 33.5e4 J/kg

What is the specific heat of a substance that requires 99,100 J ofthermal energy to heat 3.47 kg of this substance from 11°C to45°C?

1. What is the most important issue facing society today?

What is the specific latent heat of a substance having a mass of 10 kg and released an energy of 270000 KJ?

Show that ~ (p∧q) and ~p∧~q are logically equivalent

C4H6 structure that meets the conditions 1 sp, 2 sp2 and 1 sp3