dr.ampawar00

BIO 181 Genetics Problem Set Spring 2018 Part B. Sex linked genes and codominance. In humans, the gene for red green colorblindness is carried on the X chromosome (X is used for normal vision, XC is used for a colorblind allele, Y is used for the Y chromosome). This means if a male inherits the colorblind gene from his mother, he wil be colorblind. For a female to be colorblind she must inherit the colorblind gene from her mother and her father. A Punnett Square for a male with normal vision (XY) having children with a female that is colorblind (XCXC) would look as follows In this case, the female offspring would all be carriers and the male offspring would all be colorblind 1. A colorblind man marries a woman with normal vision. If the woman is not a carrier of the colorblind gene, what would you expect the phenotypic ratio to be in their offspring? 2. A colorblind man marries a woman who is a carrier of the colorblind gene. would you expect the phenotypic ratio to be in their offspring? What