If the magnitude of the surface charge density of the plates in the figure is , what is the magnitude of the electric field between the plates? If an electron is placed between the plates, what is the magnitude of the electric force on it?
For unlimited access to Homework Help, a Homework+ subscription is required.
Oppositely charged parallel plates are separated by 5.33 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? (b) What is the magnitude of the force on an electron between the plates? (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.90 mm from the positive plate?
Review. Two parallel plates having charges of equal magnitude but opposite sign are separated by 12.0 cm. Each plate has a surface charge density of 36.0 nC/m2. A proton is released from rest at the positive plate. Determine
(a) the magnitude of the electric field between the plates from the charge density
(b) the potential difference between the plates
(c) the kinetic energy of the proton when it reaches the negative plate
(d) the speed of the proton just before it strikes the negative plate
(e) the acceleration of the proton
(f) the force on the proton
(g) From the force, find the magnitude of the electric field.
(h) How does your value of the electric field compare with that found in part (a)?
Two parallel plates carry uniform charge densities -0.55 nC/m^2 and+0.55 nC/m^2.A). Find the magnitude of the electric field between theplates.B). Find the magnitude of the acceleration of an electron betweenthese plates.