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In a physics lab experiment, a student suspended a magnetic bar in between to Helmholtz coils and pointed it north. It then began to oscillate because of the earth's magnetic field. Then they pointed the apparatus south and when they applied 1 V to the Helmholtz coils the magnetic bar began to spin instead of oscillating. Why did the magnetic bar rotate? Is it a momentary effect or behavior of the apparatus at a DC supply of 1 V?

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Amal Jeeva
Amal JeevaLv10
8 Dec 2020

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

We are doing an experiment in my physics lab that involves trying to find the horizontal component of the Earth's magnetic field. Here is a little explanation of what is going on: We have a bar magnet that is placed inbetween a set of Helmholtz coils (125 of them coiled) and we place a certain current (i) on the coils. We then see that the bar magnet begins to try to align itself with the magnetic field, but it will have an angular momentum that will cause it to continue turning past the direction of the magnetic field creating oscillations. Our instructor told us to count 25 oscillations and find the time it takes for 25 to occur. From that we can then find the period of oscillations(T) from each current. Then we can find 1/T^2 from this. We then plot a graph with current(i) on the x-axis and 1/T^2 on the y axis and we find its a straight linear line. Our Instructor stated that the y-intercept will be our b and our slope will be S. From the equation given in our packet which is: (32pN x 10^-7/r x radical 125) x b/S. I know that N is the number of coils, r is the radius(9.6cm), b is the y-intercept, and S is the slope. However, from my graph, my equation for the line of best fit was y=0.967x - 0.3068. plugging this in (32p(125) x 10^-7/9.6cmx radical 125) x (.3068/.967) I get 4.643x10^-4. Putting this into gauss by multiplying times (10^4) i get 4.64 which i know is far off since NASA says its around 0.2-0.5 gauss average around Earth. I would really appreciate the help for what im doing wrong.

1. Consider the Helmholtz coils, which have 130 turns per coil.Suppose that their
diameter is 2Rcoi1 = 0.304 m. Calculate the resulting magneticfield per ampere of
current, expressing your answer in units of milliTesla perAmpere.
2. Suppose that you apply a current of 1.5 Amperes through theHelmholtz coils.
Calculate the magnetic field, in milliTesla.
3. Suppose that the electrons are accelerated by a potential V =250 Volt, and they then
move in the magnetic field that you calculated in the previousstep. If the electrons
have the accepted value of elm = 1.76 x lOll [C/kg], what will bethe radius of the
circular orbit that they make?
4. In the' experiment, you will measure r, the radius of theelectron orbit, and you will
compute B, for various values of the current I flowing through theHelmholtz coils. _
You will then make a plot, with l/r2 on the vertical axis and B2 onthe horizontal axis.
The data points will fall mainly on a straight line of slope Q. Tofind elm from this
plot, you will need an expression for elm, in terms of the slope Qof this graph. Your
pre-lab question is to use Eq. (7.5) to find this expression.Please express it in the
forn1 elm = .... , where the expression on the right-hand-sideshould include the slope
a of the plot.

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