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A skydiver of mass m jumps from a hot air balloon and falls a distance d before reaching a terminal velocity of magnitude v. Assume that the magnitude of the acceleration due to gravity is g.

-What is the work (Wd) done on the skydiver, over the distance, by the drag force of the air?

-Find the power (P d) supplied by the drag force after the skydiver has reached terminal velocity v.

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Manoj Pandey
Manoj PandeyLv10
5 Oct 2020

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

A skydiver of mass 80.0 kg (including parachute) jumps off a plane and begins her descent. Throughout this problem use 9.80 m/s2 for the magnitude of the acceleration due to gravity.
 
(A) At some point during her free fall, the skydiver reaches her terminal speed. What is the magnitude of the drag force Fdrag due to air resistance that acts on the skydiver when she has reached terminal speed?
 
(B) For an object falling through air at a high speed v, the drag force acting on it due to air resistance can be expressed as
 
F=Kv2
 
where the coefficient K depends on the shape and size of the falling object and on the density of air. For a human body, the numerical value for K is about 0.250 kg/m .
 
Using this value for K, what is the terminal speed vterminal of the skydiver?
 
(C) When the skydiver descends to a certain height above the ground, she deploys her parachute to ensure a safe landing. Usually, the parachute is deployed when the skydiver reaches an altitude of about 900 m (3000 ft). Immediately after deploying the parachute, does the skydiver have a nonzero acceleration?
 
(D) When the parachute is fully open, the effective drag coefficient of the skydiver plus the parachute increases to 60.0 kg/m. What is the drag force Fdrag acting on the skydiver immediately after she has opened the parachute?
 
(E) What is the terminal speed vterminal of the skydiver when the parachute is opened?

2 skydivers step out of opposite sides of a stationary hot air balloon 1500 meters above the ground. The second skydiver will leave the balloon 20 seconds after the first skydiver but you want them both to hit the ground at the same time. With no wind and assume all motion is vertical. To get a rough idea of the situation, assume that a skydiver will fall with the constant acceleration of 9.80m/s^2 before the parachute opens. As soon as the parachute is opened, the skydiver falls with a constant velocity of 3.2m/s. If the first skydiver waits 3 seconds after stepping out of the ballon before opening her parachute, how long must the second skydiver wait after leaving the ballon before opening his parachute? Please show as much work as possible.

2 skydivers step out of opposite sides of a stationary hot air balloon 1500 meters above the ground. The second skydiver will leave the balloon 20 seconds after the first skydiver but you want them both to hit the ground at the same time. With no wind and assume all motion is vertical. To get a rough idea of the situation, assume that a skydiver will fall with the constant acceleration of 9.80m/s^2 before the parachute opens. As soon as the parachute is opened, the skydiver falls with a constant velocity of 3.2m/s. If the first skydiver waits 3 seconds after stepping out of the ballon before opening her parachute, how long must the second skydiver wait after leaving the ballon before opening his parachute? Please show as much work as possible.

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