A bowling ball of mass M and radius R whose moment of inertia about its center is , rolls without slipping along a level surface at speed v. What is the maximum vertical height to which it can roll if it ascends an incline?
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You have a pumpkin of mass M and radius R. The pumpkin has the shape of a sphere, but it is not uniform inside so you do not know its moment of inertia. In order to determine the moment of inertia, you decide to roll the pumpkin down an incline that makes an angle θ with the horizontal. The pumpkin starts from rest and rolls without slipping. When it has descended a vertical height H, it has acquired a speed of v = √(5gH/4).
Find the moment of inertia I of the pumpkin in terms of M and R.
You have a pumpkin of mass M and radius R. The pumpkin has the shape of a sphere, but it is not uniform inside so you do not know its moment of inertia.
In order to determine the moment of inertia, you decide to roll the pumpkin down an incline that makes an angle θ with the horizontal. The pumpkin starts from rest and rolls without slipping. When it has descended a vertical height H, it has acquired a speed of v = √(5gH/4).
A bowling ball rolls down an incline without slipping. The mass of the bowling ball is 6.5 kg. The radius of the ball is 11 cm. The radius of gyration of the ball is 6.73 cm. If the incline is 10 m long and the angle of the incline is 40°, what is the speed of the center of gravity of the ball when the ball reaches the bottom?
