Log in
Physics
1
answer
0
watching
60
views

A hotair balloonist, rising vertically with a constant speed of 5.00m/s , releases a sandbag at the instant the balloon is 40.0m above the ground. After it is released, the sandbag encounters no appreciable air drag.

 

  

How many seconds after its release will the bag strike the ground?
t = __________________s
 

Watch
1
answer
0
watching
60
views

For unlimited access to Homework Help, a Homework+ subscription is required.

Sadha
SadhaLv10
24 Mar 2021

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Share

Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

A hot-air balloonist, rising vertically with a constant velocity ofmagnitude = 5.00 , releases a sandbag at an instant when theballoon is a height = 40.0 above the ground . After it is released,the sandbag is in free fall. For the questions that follow, takethe origin of the coordinate system used for measuringdisplacements to be at the ground, and upward displacements to bepositive.

part a. Compute the position of the sandbag at a time 0.270 afterits release.

part b. Compute the velocity of the sandbag at a time 0.270 afterits release.

part c. Compute the position of the sandbag at a time 1.35 afterits release.

part d. Compute the velocity of the sandbag at a time 1.35 afterits release.

A hot-air balloon is rising upward with a constant speed of 2.85 m/s. When the balloon is 3.30 m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time (in seconds) elapses before the compass hits the ground?

2 skydivers step out of opposite sides of a stationary hot air balloon 1500 meters above the ground. The second skydiver will leave the balloon 20 seconds after the first skydiver but you want them both to hit the ground at the same time. With no wind and assume all motion is vertical. To get a rough idea of the situation, assume that a skydiver will fall with the constant acceleration of 9.80m/s^2 before the parachute opens. As soon as the parachute is opened, the skydiver falls with a constant velocity of 3.2m/s. If the first skydiver waits 3 seconds after stepping out of the ballon before opening her parachute, how long must the second skydiver wait after leaving the ballon before opening his parachute? Please show as much work as possible.

Weekly leaderboard

Home
Homework Help 3,900,000
Physics 110,000
Start filling in the gaps now
Log in