a stone is thrown vertically upward with a speed of 24.0 m/s

A stone is thrown vertically upward with a speed of 24.0 m/s.

(a) How fast is it moving when it reaches a height of 13.0m?

(b) How much time is required to reach this height?

(c) why are there two answers to (b)?

answer

watching

386

views

For unlimited access to Homework Help, a Homework+ subscription is required.

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Manoj PandeyLv10

14 Oct 2020

Unlock all answers

Get 1 free homework help answer.

Already have an account? Log in

Related questions

Still not sure which equation to use. Asked previously and feel the answer was not right. Stone thrown vertically upward with a speed of 24 m/s. How fast is it moving when it reaches a height of 20.6m. Previously when asked I said 13.0 m. The answer was wrong. So I am wondering if the equation is wrong.

A stone is thrown in vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s² in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

Two stones are thrown vertically upward from the ground, one with three times the initial speed of the other. (a) If the faster stone takes 10 s to return to the ground, how long will it take the slower stone to return? (b) If the slower stone reaches a maximum height of H, how high (in terms of H) will the faster stone go? Assume free fall.