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27 Nov 2019

In procedure 2: suppose red light passes through a double slit andfalls on a screen. In the diffraction pattern, the distance fromthe central maximum to the first maximum is 5 mm.

a) The distance from the first minimum (dark spot) to the secondminimum in the diffraction pattern is
less than 5 mm
exactly 5 mm
more than 5 mm

b) Blue light has a higher frequency than red light. If you switchthe light falling on the double slit from red to blue, the distancebetween the central and first maxima on the screen would
decrease
remain the same
increase

c) Diffraction experiments are usually done with diffractiongratings (which have many slits) instead of a double slit. Theadvantage of the diffraction grating is
all the maxima are brighter
there are many more maxima generated
less light goes to the central maximum, and more to the othermaxima
it eliminates the central maximum
all the maxima are farther apart
all the maxima are closer together

d) For this question, there is more than one correct answer!
You can change L (the distance from the slits to the screen), d(the distance between the slits) and ? (the wavelength of the lightused). Which combination would double the distance between themaxima?
halve d, double ?, double L
halve L, leave d and ? unchanged
double L, halve d, leave ? unchanged
double L, leave ? and d unchanged
double L, double d, leave ? unchanged
halve L, halve d, halve ?
double L, double ?, leave d unchanged
double ?, leave L and d unchanged
halve d, leave L and ? unchanged
halve d, double ?, leave L unchanged
double L, double ?, double d
double d, halve L, leave ? unchanged

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Casey Durgan
Casey DurganLv2
27 Nov 2019

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